Program to find sum of cubes of first n natural numbers using for loop

Logic:

• Enter the number n
• sum= 1³ + 2³+ 3³ + 4³+……..+n³

Algorithm

1. Enter the number as n
2. Initially assign sum=0
3. for(i=1;i<=n;i++)
4. sum=sum + i * i * i;
5. Print sum

Program

#include<stdio.h>
void main()
{
    
    printf("***************************************************************");
    printf("\n****************************************************************");
    printf("\n**     WAP to print sum of cubes of first n natural numbers   **");
    printf("\n**               Created by Sheetal Garg                      **");
    printf("\n**                 Assistant Professor                        **");
    printf("\n**                 Phone No:9467863365                        **");
    printf("\n****************************************************************");
    printf("\n****************************************************************\n");
    int i,n,s=0;
    printf("Enter number upto which cube you want to add");
    scanf("%d",&n);
    for(i=1;i<=n;i++)
    s= s + i * i * i;
    printf("sum is %d",s);
}

Output 1

***************************************************************
****************************************************************
**     WAP to print sum of cubes of first n natural numbers   **
**               Created by Sheetal Garg                      **
**                 Assistant Professor                        **
**                 Phone No:9467863365                        **
****************************************************************
****************************************************************
Enter number upto which cube you want to add
3
sum is 36